**How do you get the complex cube root of 8? | Socratic**
https://socratic.org/questions/how-do-you-get-the-complex-cube-root-of-8

Jan 03, 2016 · The cube roots of 8 are 2, 2omega and 2omega^2 where omega=-1/2+sqrt(3)/2 i is the primitive Complex cube root of 1. Here are the cube roots of 8 plotted in the Complex plane on the circle of radius 2: graph{(x^2+y^2-4)((x-2)^2+y^2-0.01)((x+1)^2+(y-sqrt(3))^2-0.01)((x+1)^2+(y+sqrt(3))^2-0.01) = 0 [-5, 5, -2.5, 2.5]} They can be written as: 2(cos(0)+i …

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